0

158 x 20 = (158)·(20) = (150 + 8)·(20 + )
= 30x100 + (   )x10 + 16x10 + 0 =
= 3000 + (   )x10 + 160 + 0 =     3160

1

111

112

113

114

115

116

117

118

119

120

  1 of 30

FirstOuterInnerLast

 

Level

1

2

3

4

How Many

5

10

20

30

50

 

FOIL method @

 

Example >>>

 34 x 52 =  (30 + 4)·(50 + 2)

 

 

 

 

First

(A + B)·(C + D) = AC + AD + BC + BD

= 30 x 50

= 1500

Outer

(A + B)·(C + D) = AC + AD + BC + BD

= 30 x 2

=     60

Inner

(A + B)·(C + D) = AC + AD + BC + BD

= 4 x 50

=   200

Last

(A + B)·(C + D) = AC + AD + BC + BD

= 4 x 2

=       8

 

 

   

 

 

 

= 1768